1)x+y=8 and xy=12 thn column A x(1+y)+y column B 20
Ans) by solving we get x=2 n y=6 or x=6 n y=2
Sub these values in x(1+y)+y we get 20
Ans is C
2)There are 24 oranges in 1 bag.and 8 bags in 1 box then how many dozens in 24 boxes.
Ans) 1 bag contains 2 dozens
1 box contains 2*8=16 dozens
24 boxes contains 24*16=384 dozens
3) a sphere with a radius of r=1 metre....it is revolving around its vertical axis and completes one rotation in 1 second.....find the speed at which it is rotating and it is in the range of
a)0 to pie
b)1 to pie
c)0 to 2pie
d)1 to 2pie
Ans) think that the person is trying to ask the speed of not only the peripheral point but also each and every point on the sphere......
consider 'equator' of the sphere... the distance will be 2pi and in 1 sec, the speed will be 2pi cm/sec..
now consider the 'tropic of cancer'... or any arbitrary point on the sphere..... the distance will definitely be less than 2pi so speed will be less than 2pi cm/sec....
now consider the topmost point of the vertical axis. the distance covered by this point is 0 so the speed will be zero...
therefore tha answer is C. 0 TO 2PI....
4) there are "r" sections and each section is divide into "t" no.of fields and beth n jordan water these fields everyday equally ...if on monday beth does his share of watering and also 1/3 of jordans work.......then
column a column b
beths normal share rt/4
of work
Ans) beths normal share of work is same as jordan that is rt/2
that thing abt 1/3 rd work we dont have to solve anything its just to confuse tats it.....
so its A as rt/2>rt/4
5) ann deposited $10,000 for x yrs at an interest of 6%.... while david deposited $ 12,000 for y yrs at interest of 4.5%......
col A col B
amnt ann earned amnt david earned
Ans) as column a : 10000(1.06)^x
and column b: 12000(1.045)^y
x and y can take any value greater than 0 D
6) A CIRCLE WAS INSCRIBED IN A SQUARE.AREA OF SQUARE IS 36PIE.WHAT IS THE AREA OF CIRCLE.
Ans) area of square=>a*a=36pi
a=6 root pi=diameter of circle
radius of circle r=3 root pi
area of circle=9(pi*pi)
7) I DONT REMEMBER NAMES BUT LET THEM BE A,B,C.AGE OF A IS TWICE THAT OF B AND HALF OF
Ccola: col b:
average arthimethic mean of their ages 3
ans) cola:(A+B+C)/3=(A+A/2+2A)/3=A*7/6
arithmetic mean depends on A
so ans is D
8) n>1
cola colB
115n 215(n-1)
ans) is D
9) z>y>x>1
cola colB
z(x+y+1) y(x+z+1)
ans) A
10) A()B=-A^2B then find 2()-1
problem on symbol
ANS) (-2) ^2(-1)
(-2)^(-2)
1/(-2)^2=1/4
11) 1)5<9>
col A /x/ col B /y/
Ans) B
12) colA
2^7 *5^4
col B
10^4*2^3
Ans)cola
2^7*5^4
colb
(2*5)^4*2^3
2^4*5^4*2^3
2^7*5^4
C is the ans
13)A put his amount on x pecentage of intrest while B put some amount on x/2 percentage of intrest .A getting d dollars as intrest and B getting 2d dollars on intrest..(this was long narrated Q. i have writtn in brief)
colA amount of A
colB amount of B
ans) the prin. of A nd B be A & B
d=AX/100
nd
2d=BX/200
on solving, we get A=100d/x
and B = 400d/x
therefore B is the correct answer
14) In a plane ,given l and n lines are parallel.given n equation as 2y+3x=4
then wat is the slope of m?
ans) is -3/2
15) a line and circle lie in a single plane......the line passes through the circle.......
column a :it meets the circle at no.of points
column b :2
Ans) my ans is c ….correct me if I am wrong
16) word problems-----like ther is some company...it produced 30% new products last year.in that 60% were sold.what is the % of new pproducts didnt sold?
Ans) suppose total there are 100 products
30 are new and 70 are old
30% of new products are sold means 18 are sold out of 30
hence 12 new product were not sold...
they asked the percentage of the products which were not sold....12/30 x100==40%
17) if n is a +ve number then v have 3 in hundreds place n o in tens place....wats the value of N^3
ans) eg :let 30x=300
300^3=300*300*300
=270,00,000
=27 million
x can be any no from 0 to 9....x is in units place....so product is aprox 27 million
Ans is 27millions
18) the vertices of square S are (-1,-2), (-1,1), (2,-2) and (2,1)
what is the point where the diagonals of the square S meet?
Ans) consider any diagonal i.e (-1,-2), (2,1)
Mid point of diagonal=point where diagonals meet={(-1+2)/2,(-2+1)/2}=(1/2,-1/2)
19)
series 1
1,1, 11
series 2
2,2,22
col A-->std. deviation of series 1
col B-->std. deviation of series 2
Ans:mean of series 1=13/3
S.D of series 1=(10/3)root3
Mean of series 2= 26/3
S.D of series 2=(20/3)root3
B is the ans
20) For road widening the length of a rectangular plot is decreased by 15% and its breadth is
increased by 15%.
col A-->area of the original plot
col B-->area of the changed plot
Ans) the length of a rectangular plot is decreased by 15% so length=.85L
its breadth is increased by 15%. So,breath=1.15B
cola: area of original plot=L*B=LB
colb: area of the changed plot=.85L*1.15B=.97LB
ans is A i
21) k is a +ve integer. The function f(x) is defined as
f(x)= remainder when x is divided by k
==> f(x) = x%k
then what is the value of k , if f(k+25)=3
Ans: then what is the value of k , if f(k+25)=3
c the function goes like k+25%k=3
now for k+25 to be exactly divisible by k u will have to subtract 3 so the function should be k+22
now k+22/k is perfectly divisible
so 1+22/k only 2 and 11 r factors of 22 so take k as 2 and 11
thus 11 is the answer as 2 does not fit
22) two cylindrical containers are there. one with internal radius 3 inches other with internal radius 6 inches. The 3 inch cylinder is of 10 inch height of which upto 9 inches was filled with a liquid. what would be the depth of the the liquid in the 2nd container if 1st container is emptied into the second container(previously empty)
Ans: 1st Cylinder small 1. Where the data for Cylinder is r =3, h=10
But the Liquid is filled up to 9....
Volume of liquid in 1st Cylin = Volume of Cylinder ( only till h = 9 )
= pie*r^2*h
=pie*3^2*9 ( eq 1 )
NOw tht is pour in Cylinder 2....Where the data for Cylinder is R =6, H=x
Now Volume of liquid in 2nd Cylin = Volume of liquid in 1st Cylin ( only till h = 9 )
pie*R^2*H = pie*3^2*9 [From eq 1 ]
pie*6^2*H= pie*3^2*9
Just calculate
H= 2.25
23) xy>0
col a:--> y
col b:--> 0
Ans: D
24) z= [(123)^4]-[(123)^3]+[(123)^2]-(123)
if z is divided by 122 what is the remainder?
0....1....2....3....4
Ans: take 123^3 common from 1st bracket n remaining will be
({123-1}=122)... nsimilarly 123 from 2nd bracket n we get{(123*122)nnn finally take 122* 123 from d result
Ans is 0
25) A circle is inscribed in a square.
col A colB
diameter of circle diagonal of square
Diameter of a circle=side of a square
Diagonal of a square>side of a square
Ans is B
26) a@b is defined as -(a to the power -2b) so what is the value of 3@2
a)12 b)-81 c)1/81 d)-1/81 e)-12
ans is -1/81
27) circle and line lie on the same plane
line l passes through the centre of the circle
cola col b
no.of points the line 2
intersects with the circle
Ans is C
28)probablity question : they have given 3 bags all have red and white marbles: in first bag 4r n 6w second bag : 5r , 6w and third bag 5 red 5 w , they asked: if 1 marble is taken from first bag and tarsfer to second bagand then 1 ball from the second bag is chosen.....now calculate the probability of the ball chosen from the second bag being red..... ?( they gave numbers to the bag so no need of third bag it is just for confusion)
ans)
:(4c1/10c1 * 6c1/12c1)+ (6c1/10c1 * 5c1/12c1)
29)a 5-ltrs jug contains 4-ltrs of salt water solution that is 15% salt..if 1.5 ltrs of solution spills out of the jug,,n the jug is then filled to capacity wth water,,approximately what % of resulting solution in the jug is salt?
a)71/2 % b)93/8 % c)101/2 % d) 12% e)15%
ans) in 4 litre solution salt is 15% i.e. 600 ml. so in 1 litre amount of salt present is 150ml. out of 4 litre 1.5 litre spilled out i.e. 225 ml spilled out. so remaining salt in 2.5 litre solution is 375ml. n now only 2.5 litre water wil be added in remaining solution. hence in 5 litre solution only 375 ml salt is present which is 7.5% of total solution
30) parallegram opposite angles are given 7x,120
another angle 3y col b
x y
ans) in parallelogram opposite sides are equal
so 7x=120 => x=120/7
sum of other two opposite angles=360-240=120
=>3y=120 => y=60
Ans is B
31) a triangle was given angle ABC is 40,he asked the sum of two exterior angles at the base.i.e AC extend AC on both the sides..
such that one angle is X and other Y..(external angles)
wat is the value of X+Y..
ANS) X+Y=A+C+40+40
A+B+C=180
A+40+C=180
A+C=140
X+Y=140+40+40=220
ans:220
32)given z=4^x+4^x+4^x+4^x.and asked to find z^2
ans): z=4*4^x=4^(x+1)
z^2=4^2(x+1)=16^(x+1)
33) col a:(5+1/4)^2+(5-1/4)^2
col b:50
ans: cola:50+1/16+1/16
colb:50
ans is A
34 )given that avg of y women is (),avg of m men is 60,avg of age of both of them is 56.
cola:y
colb:m
ans:
35)two computer square chips r there x,y.side of y is 0.1 more than that of x and the area of y is 0.75 more than that of x.find the side of y.
ans) y=x+0.1
(x+0.1)^2=0.75+x^2
On calculating x=3.7
Y=3.7+0.1=3.8
ans:3.8
36)a rectangle was inscribed in a circle,diameter was given,side s of rectangle were x,2x.asked to find the area of rectangle.
ans:32
37)one di question relating to full time and part time employees,
ans:3/16
38)col a:no from 1 to 100 inclusive,which do not contain multiples of 3 but have multiples of 7.
col b:10
7,14,28,35,49,56,70,77,91,98 are the multiples of 7 which are not multiples of 3
Total 10
ans:c
39) 1)5/0.09
2)0.5/0.9
3).05/.00009
4)0.005/.09
5)5000/90
wats the least of the given values...
ans) 1)500/9
2)5/9
3)5000/9
4)5/90
5)5000/90
4th option is the least of all
40) Quadrilateral ABCD
angle DAB=60degrees
angle ABC=95 degrees
and AD is extended to E, E joined to C such that B,C , E are in a straight line
similarly AB is extended to F , and F also joined to C such that D,C,F are in a straight line
then angle EDC=alpha degrees
angle BFC = beta degrees
column A
alpha
column B
beta+55 degrees
Ans) cola:alpha = beta + 60
41) two numbers A and B lie in between 240 and 290
tens place of A is 8,units place is x
tens place of B is 6, units place is y
column A
A-B
column B
20
Ans) A=28X B=26Y
Consider max of 28X n min of 26Y i.e 289 n 260 =>A-B=289-260=29
Consider min of 28X n max of 26Y i.e 280 n 269 =>A-B=280-269=11
Ans is D
42) n>2
: column A-----115*n
column B-----215(n-1)
Ans) consider n=2.1 cola > colb
Consider n=3 cola <>
Ans is D
43) y=10x +7 col a tens digit of x col b units digit of y
Ans) is D data insufficient
44) 1) ratio of prob of divisibles of 3 between 1-50&51-100;
ans) 16:17
45)
if 1<3>
col a;4x/3; --------------- colb;4x-3
Ans) let x=1.1 then 4x/3=4.4/3=1.46
4x-3=4.4-3=1.4
Let x=2 then 4x/3=8/3=2.6
4x-3=8-3=5
Ans is D
46) how many 3 digit nos are der between 100 to 999 whose units place is 2 nd is a perfect squre ....
ans) is 0
47) A ladder of 5 ft length is in a slant position against a wall. The base of the ladder is
pulled y ft away from the wall and so the top of the ladder moved x ft towards the ground.
col a:--->x
col b:--->y
Ans) is D data insufficient
48) a rectangle was of side 8 & 4 and qudrilateral is given and the side of quadi is the side of rectangle i.e 8 n the angle made by the quadi and tri is 45deg
cola col b
area of the quadi 15
49) One Biggest rectangle contng a smaller one, a a smallest rectangle inscribed in that smaler rectangle. The length and breadth of biggest one are 8x4. the length and breadth of biggest one is four times than that of the smallest one. the length and brdth of biggest one is twice than that of middle one. the region of smallest rectangle and the biggest one except the middle rect are shaded and they asked to find the area of the shaded region.
ans. Area of big rect 8*4=32
Area of small rect=2*1=2
Area of middle rect=4*2=8
Area of shaded region= 32-8+2=26
50) A tabulated colums r given.
classes medianscore no of students
classA 74 50
classB 78 65
cola colB
median score of 115 stdnds 76
51) l3x-2l = 4
colA colB
lxl 4
Ans) x=2 n -2/3 only satisfies |3x-2|=4
|2|=2<4
|-2/3|=2/3<4
Ans is B
52) a set of n numbers each having value 8 and the set of other n+2 nos each having values 10 .find arethmetic mean of all the nos.
Ans) (8n+10(n+2))/n+n+2
=> 18n+20/2n+2
=>(9n+10)/(n+1)
=>82/9
53) barx= 1-x, then for all values of x, y=barx, then find value of barY.
Ans) Y=1-x
Bary=bar1-x=1-(1-x)=x
54) colA colB
1/.001+1/.9999 1/.002+ 1/.998
Ans) 1000+10000/9999 > 500+10000/9980
Ans is A
55) 4*(14^10)*(7^2)
Ans) 2^2*(2^10*7^10)*7^2
=>2^12*7^12
=>(2*7)^12
=>14^12
56)Acircle with an angle inscribed in semicercle of it. the arms of the angle other than diameter are 6 & r then find area of circle.
Ans) angle subtende by diameter is 90 so it is the hypotenuse =2r
Applyng pythogerous theoreme (2r)^2=6^2+r^2
4r^2=36+r^2
3r^2=36
r=2root3
area of circle= pi*r(2root3)^2
=12pi
57) An empty swimming pool can be filled to capacity through an inlet pipe in 3 hours, and it can be completely drained by a drainpipe in 6 hours. If both pipes are fully open at the same time, in how many hours will the empty pool be filled to capacity?
A. 4
B. 4.5
C. 5
D. 5.5
E. 6
Ans) it takes 3 hrs to full the tank and 6 hrs to empty so if the both pipes are started for every 3 hrs the tank empties to half..{half tank} so to fill completely it takes another 3 hrs ...i think u got it........the ans, is 6hrs
58) the number of 7 digit arrangements of a,b,c,d,e,f,g, with d in 4th place..
Ans) 6!=720
59) A motorcycle stunts man belonging to a fair, rides over the vertical walls of a circular well at an average speed of 54 kph for 5 minutes. If the radius of the well is 5 meters then the distance traveled is:
A. 2.5 kms
B. 3.5 kms
C. 4.5 kms
D. 5.5 kms
E. None of the above
ans) distance traveled=v*t=54*5/60=4.5kms
radius is given to confuse u
60) If 1 cm on a map corresponds to an actual distance of 40 kms. And the distance on the map between Bombay and Calcutta is 37.5 cms., the actual distance between them is :
A. 375 kms
B. 3750 kms
C. 1500 kms
D. 1375 kms
E. None of the above
Ans) 37*40=1480km .5cm=20km
(37+0.5)cm=1480+20=1500km
61) A box contains 90 nuts each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg., then the weight of the empty box is :
A. 10 kg
B. 10.5 kg
C. 11 kg
D. 11.5 kg
E. None of the above
Ans) 90*100=9000gm=9kg
100*150=15000=15kg
Total=24kg
Weigh of empty box=35.5-24=11.5
62) If the radius of a circle is increased by 20% then the area is increased by :
A. 44%
B. 120%
C. 144%
D. 40%
E. None of the above
Ans) let r=10 area of circle=100pi
Radius increased by 20% …now r=12
Area of circle=144pi
Area increased by 44%
63) If x, y, and z are consecutive negative integers, and if x > y > z, which of the following must be a positive odd integer?
A. xyz
B. (x - y) (y - z)
C. x - yz
D. x(y + z)
E. x + y + z
ans) let x=-2 ,y=-3, z=-4
substitute in the given options
only B gives a positive odd integer
64) xy is not= 0
col a: |-x-y|
col b: x+y
ans)
i think ans is D....bcoz take x= -1 n y=-1 then cola :2 colb:-2
now Take x=1 n y=1 then cola:2 colb:2
65) a triangle is given and in that taking vertices as centres arcs were drawn with 2 cm as radius so that it symbolizes like angles as we represent in geometry and was told to find the length of the arcs
ans) sum of 3angles =180..ie 1/2 of the full circle.i asked 2 find d lenght of the arc...so its
length of arcs ie circumference when 360 =2*pi*r
when it is 180 length= ½* 2pi*r=1/2*2*pi*2=2pi
66) at a dress show room a dress was sold with profit at a rate of 20%......what is the % of profit in the cost price
Ans) let cost of dress be 10
Sold at a rate of 20% profit=20/100*10=2
Cost price of dress=10
Q is what is the % of profit in the cost price
what is the % of 2 in the 10=20%
ans is 20%
67) Mean weight of apples in a basket is 4 ounces, and their standard deviation is 0.8.
Col A : The weight of the apple with 1.5 standard deviation
Col B : 3.2 ounces
Ans) mean weight of apples=4 n SD =0.8
Standard deviation depends up on the the deviation of the weight of apples from its mean weight
Apple with 1.5 SD mean its weight deviated from mean weight i.e 4.this deviation may be +ve deviation or –ve deviation
That means weight of the apple may be >4 or <4
So, ans is D
68) . Square with an inscribed circle(fig. given) with radius r. Area of the shaded region.(which was 1/4th of the region left out in the square... hope its clear)
ans) side of aquare=2r
Area=4r^2
Area of shaded region =4r^2-pi*r^2
69). Given that xy>0
Col A : x+y
Col B : 0
Ans. D
70) n is the least possible no. such that 18n is a perfect square. m is the least no. such that 9m is a perfect square.
Col A : n
Col B : m
Ans.) 18n=18(2)=36
9m=9(1)=9 m=1 n=2 here n>m
well if n & m not given interger than u`l have to take n = 1/18 and m = 1/9 so m > n...
ans is D
.
71) One triangle made inside the other (Let me try and xplain the diagram say PQR is inside XYZ such that PQ || XY and QR || YZ and P when extended meets X and R when extended meets Z) Now external angle at X is x. Internal angle at P is y. and internal angle at Z is z.
Col A : x
Col B : y+z
Ans. C they are equal.
72) (14^10+7^2)^2-(14^10-7^2)^2
Ans) it is in the form of (a+b)^2-(a-b)^2=4ab
Where a=14^10 n b=7^2
(14^10+7^2)^2-(14^10-7^2)^2=4*14^10*7^2
2^2*(2^10*7^10)*7^2
=>2^12*7^12
=>(2*7)^12
=>14^12
73) 2, 3, 5, 8, 7 , 9 r all +ve integers ..... if three digits nos r taken using each number only once... then.
col A -. the maximum possible sum of the numbers.
colb -> 1459
Ans) max possible no=952+873=1825
Ans is A
74) . col a--------------------------------------- col b
(2^7)(5^15)+(2^7)(5^15) --------- (5^7)(10^8)
Ans) cola:2^8*5^15
Colb: (5^7)(2^8*5^8)
2^8*5^15
Ans is C
75)|6-x|-|x-3| ....find the value if x=-3.
ans) |6+3|-|-3-3|=9-6=3
76) in one vase there is some tulip &rose. prob of rose is k & that of tulip is 2k.
col a=k
col b=1-k
ans b
77) one di q that was of like if 16 men have to be carried in a 3 boats the same q discussed many times...
ans:1>1/4
78) if x,y,z are divisible by 7 and remainder is 3 then wat is the remainder wen x+y+z is divided by 7.
ans: let x=7+3,y=14+3,z=21+3 gives reminder 3 when divided by 7
X+y+z=51
51/7 gives reminder 2
Ans is 2
79) if p is a positive integer then how many values will there 4 p such that 36p is a factor of 720
Ans) 1,2,4,5,10,20 36*20=720….indirectly factors of 20 will be the ans
Total 6 values
80) if net income=annual revenue-expenditure and if net income=4*expenditure then wat is expentiure as a fraction of annual revenue.
ans:given I=R-E n I=4*E
4E=R-E
5E=R
E=1/5*R
Ans is 1/5
81)
a no was given like H_P0__ 4
for the first blank can be a letter from 26 alphabets for the 2nd and 3rd blank is a digit then wat is total combination (different)
ans):26*10*9
82) ....If a cmpny R has 50 more employees then S and another company T has 1/4 no of emloyees of R .
col a col b
no of employees no of employees in a company T
in a company S
ans) R=50+S
T=R/4
Let S=50
then R=100
T=100/4=25
S=50 and T=25
Ans is A
83)
15<30
25<35
cola colb
y-x 0
ans) case1: let x=16 n y=34 y-x=18
Case2: let x=29 n y= 26 y-x=-3
So ans is D
84)
col a
root(26) -root(17)
col b
root(26)- root(17)}^2
Ans) is A bcoz {root(26) -root(17)}<1
.85) x<2>
Ans ) case 1: let x=1 n y=2 xy=2<6
Case 2: let x=-3 n y=-4 xy=12>6
Ans is D
86) a person spends same amount from his salary everymonth.Last year if he spends 6 months of salary . then wht fraction of salary he spends everymonth.
Ans) : 1/2.
87) the ratio of circumference of 2 areas is 4:1 find ratio of their areas.
options were 2:1 4:1 12:1 8:1
ans) let it be circumferences of circle
2*pi*r1=4 n 2*pi*r2=1
r1=2/pi n r2=1/(2*pi)
ratio of their areas=pi*r1^2:Pi*r2^2
=r1^2:r2^2
=4/pi^2:1/(4*pi^2)
=4:1/4
= 16:1
88) two lines are parallel n and p, two line l and m intersect n at a point.such that a triangle is formed between n and m. we need to find if the two sides of the triangle are equal or not. its comparison question. the third side is base of p.
Ans ) is D
89)
2.007/.007 + 2.007/7
ans) 2007/7+2.007/7=2009.007/7=287.001
90) R is a multiple of 3 and S is a multiple of 7 what is the least number that divides the product of R and S exactly options were like 21,42 168 dont remember the options exactly
ans) 3 is a multiple of 9
7 is a multiple of 21
R*s=9*21=189 is divisible by 21
91)there were 60 chocos divided amond jan, philip and phylu jan got more than philip and got more than phylu also
colA colB
number of chocos jan got 21 or 22 dont remember exactly
ans) jan should have min 21 chocos to be more than Philip n phylu
Ans is D
92) draw the figure...
draw two lines AB n BC so that they form an angle at B.
noe draw two lines from point B so that they make an angle 'a'mark the line nearer to A as L and other one nearer to C as 'M .
NOW AngleABM='x'=74 degrees(given) n
AngleLMB='a' = 20 (given)
Angle LMC='y'
And Angle ABC=82degrees( given)
think u got the diagram
find x-y
so 'y'=(ABC-x)+a
u will get y=(82-74)+20--------y=28
finally x-y=74-28==========46degrees is the answers
93) x=10y+2
cola: tens place digit of x
colb:units place digit of y
ANS) ans is D ie cant be determined
--
take x = 22 then y =222 here it seems ans is b
take x= 82 then y= 822 here its a.
therfore ans: d
94) Two circles A n B.A's diameter is half of B's Diameter.
Cola:no.of revolutions A makes in 5000m
colb:NO.of revolutions B takes toin 2500m
Ans) for one revolution A ---covers 2*pi*r distance
for one revolution B ---covers 2*pi*(2r) distance
let X be no of revolutions by A in 5000 meters
then X*2*pi*r = 5000
let Y be no of revolutions by B in 2500 meters
then Y*2*pi*(2r) = 2500
divide both the values
[ X*2*pi*r]/[Y*2*pi*(2r)] = 5000/2500
by implifying we get
X/(2*Y) = 2
X= 4Y
Answer is A.
95) )g(X)=3power(x-1)
then( g(x+1)-g(x))/2=(3^x-3^(x-1))/2
=3^x(1-1/9)/2
= 3^x*4/9
96) y<0 2="y^2+5
col a:x
col b:y
ans) is D
97)col a:2^-3+4^-3
col b:6^-3
ans) cola:1/8+1/64=9/64
Colb:1/216
Ans is A
98 )given n is a two digit no: in which unit digit is 5 and n^2 in which thousands place is 3 and hundreds place is 0....find n?
1)35
2)45
3)55
4)65
ans) is 55 55*55=3025
99) supoose we have two cubes having volume x an 2x...
col a
the ratio of their sides
col b
.5
ans ) lest sides of cubes be s1 n s2
S1^3=x ,s1=cuberoot(x)
S2^3=2x ,s2=cuberoot(2x)
s1/s2=cuberoot(x/2x)=cuberoot(.5)<.5
ans is B
100)there are 15 questions out of which any 12 can be chosen...
find the no of ways it can happened??
ans) 15C12= 455
101)company r has 60 more people than s
and t have 3/4 of the r
col a people in s
col b people in t
ans) R=60+S
T=R/4
Let S=40
then R=100
T=100*(3/4)=75
S=40 and T=75
Ans is B
102) 2)there are totle 15 boys. select 12 out of 15 & selection of 12 is done randomly. than probebility of there selection.
A=455
B=300
C=60
D=15
E=12
ans) 15C12=455
103) COL A= no b/n 1 to 50 inclusive both that divisal by 3
col b = no b/n 51 to 100 inclusive both thqt divisal by 3
ans ) cola:16 colb:17
Ans is B
104) they given that 49^x=47 and ask to find the value of 7^x
ans) (7^x)^2=47
7^x=root(47)
105) Image that a circle inscribed in square. side of the squre is 60 m. find fraction of are that not cover by the circle.
ans) (3600-900pie)/3600
=3600/3600-900pi/3600
=1-pi/4=(4-pi)/4
106) given that n is number. when n divide by 7 it gives remainder of 3. then find remainder when n^2-5 is divide by the 7
A=2
B=4
C=6
D=8
E=10
ans) let n=7+3=10
n^2-5=10^2-5=95
95/7 reminder is 4
107) 1 kg=2.2 pounds x
col a---no of pounds for x kgs
col b--no of kgs for y pounds
ans) case1: let x=2 n y=4.4
Cola:4.4 colb:2
Case2: let x=1 n y=6.6
Cola: 2.2 n y=3
Ans is D
108) 5 numbers were given
col a--SD if 150 is added 2 each number
col b--SD if 10% of each number is added 2 the respective number..
ans) let the numbers be 10,20,30
cola:
150 added to each number so SD doesn't change
SD=root{((10-20)^2+(20-20)^2+(30-20)^2)/
3}=root{(10^2+10^2)/3}
colb:
10% of each number is added...
so numbers are 11,22,33
SD={((11-22)^2+(22-22)^2+(33-22)^2)/3}=root{(11^2+11^2)/3}
colb is greate
109) From 1 to 2000 how many of the cubes are eqqual to the no of squares
ans) 3 no’s are 1,64,729
110) a circle of radius r1 and the radius of inner circle is r2.
col a
what is the probabality of a point occuring in the path between two cirlcles
col b
¾
Ans) cola : 1/5 1)outside circle r1
2)on the circle r1
3)in b/t circles r1 n r2
4)on circle r2
5) inside circle r2
Colb: ¾
Ans is B
111) )The average daily temperature in San Francisco for the month of February 2000 is 45 degrees. The average daily temperature of the first 15 days and the last 15 days of February 2000 in San Francisco is 44 degrees and 46 degrees respectively. What is the temperature On 15 February 2000 in San Francisco?
43 F
44 F
45 F
46 F
47 F
Ans) first 15 days 1-15 avg=44
Last 15 days 15-29 avg=46
So avg on 15th day=(44+46)/2=45
112) 18)This is about Avg marks of students in 3 classes
Class average
Class 1 82
Class2 88
Class3 90
Overall avg
Of 3 classes 86
Col a Col b
No. of students No. of students
in class1 in class2
Ans) let x= no of studs in class a
let y="---" b
let z="----" c
(84x +88y +90z )/(x+y+z) = 86 .
solve and u get:
-2x + 2y + 4z = 0.
>> x=y+2z
therefore here x,y,z cant be negative,hence: x > y and x > z
ans: col A.
113) )a man sold product X for 25% profit and Y for 25% loss..if he sold them for 210000 each then the sum of their original products is how much greater than 420000?
1.0
2.14000
3.36000
4.42000
5.28000
Ans) product x : (25/100)*x+x=210000
x/4+x=210000
x=168000
product y: y- (25/100)*y=210000
y=280000
x+y=448000
original product is 448000-420000=28000 greater than 420000
ans is 28000
114) diameter of a circular region of area 4pie is used as unit of length how many units of lenghts is diameter of a circular region of area 100pie
5
10
12 1/2
20
25
ans) pi*r^2=4*pi
r=2 d=4
pi*r^2=100*pi
r=10 d=20
4*5=20 so,5 units length is diameter of a circular region of area 100pi
116) cola (35^1/2-26^1/2)^2 col b (35^1/2-26^1/2)
Ans) root 35 is 5. smthing and root26 is also 5. smting
so if u substract we get a value > 1
so the ans is col a
117) 1. Sr
Find relationship b/w them
ans) s
1181) 2^y=16
Find the value of y.
ans) 2^y=2^4
Y=4
119). Col A 1+1/3+1/6+1/10
ColB 2
ans) ans is B
120) . Area of circle is 36pie find the diameter.
Ans) PI*r^2=36*pi
r=6
Diameter=12
121) Let D be a decimal of the form, D = 0.0a1a2a1a2a1a2……….., where digits a1 & a2 lie between 0 and 9. Then which of the following numbers necessarily produces an integer, when multiplied by D?
(1) 18 (2) 108
(3) 1980 (4) 208
(5)408
Ans) multiply the eqn first by 10, then multiply THAT eqn by 100...
subtract them nd you'll get
D= a1a2/990
which means that D should be multiplied by a multiple of 990 to get an integer...
in the list the multiple is 1980 so that's the answer
122) 4.) An angle BAC is 82 degrees..angle A is divided by two lines....one forming an angle x degrees n other y degrees wit B n C respectively...value of X-Y???
Ans) ans is D bcoz x-y can be >1,<1>
123) If 7 ppl work for 140 hrs overtime...4 ppl work for h hrs....n 3 work of 2h hrs..wht is the diff b/w avg n median ??
Ans) 4h + 3 (2h) = 140
h = 14
so 4h = 4*14 = 56
3h = 3*28 = 84
so average = 56+84/7 = 20
median = 14, 14, 14, 14, 28, 28, 28
so median = 14
so difference is 6
124) classes score
1 88
2 82
3 90
total avg=86
col a
No. of students in class 1
col b
No. of students in class 2
Ans) let x= no of studs in class a
let y="---" b
let z="----" c
(84x +88y +90z )/(x+y+z) = 86 .
solve and u get:
-2x + 2y + 4z = 0.
>> x=y+2z
therefore here x,y,z cant be negative,hence: x >y and x>z
ans is A.
125) A tree grows for 6 weeks..1st week it grows 1/4..then 1/5.then 1/6...then 1/7..then 1/8...then 1/9....Second tree grows 3/4th in 6 weeks...
col a col b
total growth of tree 1 total growth of tree 2
Ans) ans is D
bcoz we dono the heights of both trees....we can't tell which tree grows larger
126) 20% of 1/16 25% of 0.05
Ans) cola:1/80 colb:1/80
Ans is C
127) cola
1+2*square root of 3
colb
3+square root of 3
Ans) cola:1+2*1.7=4.4
Colb:3+1.7=4.7
Ans is B
128). 33<35>
Col A: The number of factors of X including 1 and X….
Col B: 4
ans) x=34 factors are 1,2,17,34
Ans is C
129) The average of 6 numbers is n if a number is deleted from that, then the average of 5 numbers is n-2….then what is the number deleted….
A. n+10
B. n+5
C. n
D. n-2
E. n-10
Ans) S5=sum of 5 numbers x=number deleted
(S5+x)/6=n S5/5=n-2 => S5=5n-10
5n-10+x=6n
X=n+10
Ans is A
130) Given a triangle with two angle 60 (which means it is an equilateral triangle ) and two side are given as x+4 and y-3
Col A Col B
x y
ans) y>x for all values
Ans is B
131) In a country the only 13 ppl were currently using cell phones and it is expected that it will increase to 925%in the next 10 yrs .How many ppl will be using cell phones after 10 yrs.(wordings and number may change i dont remember exaclty BUT THE SENSE is the same)
Ans) ans is 133
for 900% inc ppl=13*9=117
for 25% inc ppl=3.25
for 925% inc ppl=117+3.25+13=133.25=133
132 )GIven a triangle ABC in the coordinate axis. the coordinates of all the three points A,B,C were given and angleB is given as x
Col A Col B
x 90
ans) as the coordinates were given u got to find the distance they will be root20,root5 and 5
They follow pythogorous theorm so x=90
ANS is c
133) one question was about exponents and bases all u had to know is the basic formulae like x^a * x^b=x^(a+b), (x^a)^b=x^ab and so on
I dont remenber the numbers the answer was 14^12
134) ((x-1)^2 )-1 <0
Col A Col B
x 2
ans) (x-1)^2<1
(x-1)
(x-1)<1
X<2
Ans is B
135) Wt is the least product that can be formed by -5 to 4 inclusive
A)-60 B)-120 C)-180 D)-240 E)-500
ans) -5*-4*-3*-2*-1*2 ==-240
D is the ans
136) 9) if |a|+|b|>|a+b| then which must be true
I eleminted all the option expect 2
a)ab<0
b)a+b<0
Ans) is ab<0>
137) |3x+2|=8
A B
X 3
Ans) x=2 r -10/3 which r less than 8
Ans is B
138) A(B)= -(A-2B),then what is the value of 3(2)?
Ans). 3(2)=-(3-2x2)=-(-1)=1
139) S=Set of integers which are multiple of 6
T= Set of integers which are multiple of 8
No. of integers from 1 to 100 which belong to both the sets?
Ans. Its 4.(24,48,72 and 96)
Just write either of the two integer table and follow the conditions given.
140) If x is a positive integer, and 2 is a factor of 3x+1 then,
A B
(-1^x) 1
Ans is B. Because for 2 to be a factor of 3x+1, x should always be odd and –1 to the power odd is always –1.
141) Volume of cubes A and B are x and 2x respectively,x is a positive integer.
A B
Ratio of length of cube A
to the length of cube B ½
Ans) side of cube A=cuberoot(x)
Side of cube B=cuberoot(2x)
Ratio=cuberoot(1/2)<1/2
Ans is B
142) A B
(0.001)-1 + (0.9999)-1 (0.002)-1 + (0.9998)-1
Ans) (1.0009-2)<(1.0018-2)
Ans is B
142)From the figure below, it was asked that if AD=DC,and the co-ordinates of all the three vertices of the triangle were given.(D is between A and C)
A B
Area of triangle ADB 10
Ans is C
143) No. of articles sold 15 10 30 45
Price per unit( in dollars) 10.15 18.5 14 12
What is the approximate average price per unit?
Ans) sol:
(15*10.15+10*18.5+30*14+45*12)/(15+10+30
+45)=12.97
144) 12 people sitting around a circular table each will require minimum place of 2.75,what is the least dia of table possible
Ans) circumference of table=2*pi*r=12*2.75=33
R=33/6.28=5.25
Diameter =10.5
So,least diameter of table possible=11
145) IF A&B are no’s from 200 to 999 and
tens place of A is 8
tens place of B is 6
column A column B
A-B 2
Ans) A=x8y B=a6b
X and a need not be equal
Ans is D
146 )A triangle ABC was inscribed in a semi circle and sides of the triangle were given 6&8 and a line is drawn from vertex of triangle to the center D and asked to find the lenth of line of B to D it becomes radius of triangle
0 6 8 10 12
ANS) :10
147) Area of a circular region given 250 and asked to find the radius of the circular region
Ans) pi*r^2=250
R=8.9
148) One std dev problem was given the median of 101 numbers is 50 and the std devation is zero.
Cola Col B
Average arthematic mean of 101 numbers 50
ans) std deviation becomes 0 only when all the 101 numbers are equal
median is given as 50 ...so all 101 numbers are 50
so arithmetic mean=50
ans is C
149) if 3 books are moved from shelf S to shelf T then both S and T will be having the same number of buks....and if 7 buks are moved from T to S then S will be having 3 times
ans) s-3=t+3
3(t-7)=s+7
solving this we got
s=23
t=17
150) col a col b
2^-3*4^-3 6^-3
ans) cola: 8^-3=1/8^3
colb:6^-3=1/6^3
ans is B
151) cola colb
1/101+1/102+1/103 1/103+1/102+1/101
Ans) both are equal C is the ans
152) avg in 3 tests 86 how much should get in 4th to score avg 89
Ans) S3=sum of first 3 tests
S3/3=86 => S3=258
Let x be the 4th test score
(S3+x)/4=89
258+x=89*4
X=356-258=98
98 is the ans
153) cola colb
4*100^2 .004*100^2
Ans) A is the ans
154) cola colb
sum of the squares of sum of the squares of
first 100 even numbers first 100 odd numbers
ans) cola: 0^2+2^2+4^2+6^2+…….+198^2
colb: 1^2+3^2+5^2+7^2+……..+199^2
if u compare 1st 2nd 3rd…..100th term of cola n colb ….colb have high value numbers
ans is B
155) UTAH & MAINE..there are these to words..
if u choose 1 alphabet from,what is the probablity that they are not same..
ANS):8/9 there are 8 unique words
total no of words=9
156 )There is code that is of the form..
_ _ _ _ _..ie 5 blank spaces..
first there 3 blank can take any alphabet(expect the vowels)..repetation allowed
and last 2 blank any no from 0-9..repetaion allowed..what r the diff poss values?
ANS):21*21*21*10*10
157) A right angle triangle lies inside a semi-circle such that,the hypt=diameter of the semi-c..
remaining two sides are x & y..
col A:x*x+y*y
col B:4r*r..
ANS): cola: x*x+y*y=(2*r)^2=4r*r
Colb: 4r*r
Ans is C
158) consider triangle ABC..
Ang ABC=40..
AC is the base..
extend AC on both the sides..
such that one angle is X and other Y..(external angles)
wat is the value of X+Y..
ANS) X+Y=A+C+40+40
A+B+C=180
A+40+C=180
A+C=140
X+Y=140+40+40=220
159)For road widening the length of a rectangular plot is decreased by 15% and its breadth is increased by 15%.
ANS A
col A-->area of the original plot
col B-->area of the changed plot
Ans) the length of a rectangular plot is decreased by 15% so length=.85L
its breadth is increased by 15%. So,breath=1.15B
cola: area of original plot=L*B=LB
colb: area of the changed plot=.85L*1.15B=.97LB
ans is A
160) .a vas contg onlyroses and tulips. probability for taking roses is k and that for tulips is 2k.
colA colB
k 1-k
Ans) let no roses=x
No of tulips=y
Probability for taking roses=k=x/(x+y)
Probability for taking tulips=2k=y/(x+y)
1-k=1-x/(x+y)
=(x+y-x)/(x+y)
=y/(x+y)
=2k
B is the ans
161) 2.007/.007+2.007/2 is approximately = ?
a)0
b)30
c)s.t
d)300 (
ans) :D we 'll get approx. 287.7)
162) (4x-2y)(6x+3y)=18
cola
4x^2 - y^2
colb
6
Ans) 24x^2+12xy-12xy-6y^2=18
24x^2-6y^2=18
6(4x^2-y^2)=18
4x^2-y^2=3
163) if n is a positive integer then
cola
no.of +ve factors of 2n
colb
no.of +ve factors of n
ans) ans is A
164) a square is given of area 80 is cut 2 sides parallelly.....after cutting only 3/4 is remaing
Ans) 3/4th of 80 =(3/4)*80=60
Remaining area =60
165) a1=5 a2=10 a3=10^5
in general an=[a(n-1)]^[a(n-2)]
no of digits in a5?
ans) :
Now you know a1=5
a2=10
a3=10^5
And we have an formula i.e an=[a(n-1)]^[a(n-2)]
you need a5........Just substituite n= 5 in question .....
so a5= [a(5-1)]^[a(5-2)]
= a4^a3
We dunno a4.......calculate a4.............Just substituite n= 4 in question .....
a4= [a(4-1)]^[a(4-2)]
=a3^a2
=(10^5)^10
=10^50
Subs back again a5= a4^a3
a5 =a4^a3 =(10^50)^(10^5) =(10^50)^(100000)
=10^(5000000)
there fore no of digits 5000001
166) 1,2,3,4,5 r the five numbers given
prob of selecting 2 numbers tht their product is an odd number..
Ans) product of two numbers is odd when both the numbers are odd
Probability=3/5*2/4=3/10
167) Col A
Sum of first ten even numbers
col B
sum of first ten odd numbers
ans) cola: 0+2+4+6+8+10+12+14+16+18
colb: 1+3+5+7+9+11+13+15+17+19
comparing 1st,2nd….10th terms of cola ans colb
colb has greater numbers
ans is B
168) a number when divided by 3 leaves a remainder 1. whent the same number divided by 15 leaves the remainder 13?
Options: 15,27,35,43
Ans) by elimination 43 is the ans
43%3=1
43%15=13
169) A(*)B = (A^2 - B^2)\AB
Col A : A(*)B
Col B : B(*)A
Ans) col a: (A^2 - B^2)\AB
Col b: (B^2 - A^2)\AB
we don’t know the values of A & B
ans is D
170) Total Annual income of 600 companies are determined. From this Estimated Annual Incomes(EAI) are determined. F,G,H are three companies which have EAI as 30,40,and 60 percentile of the total.
A
Difference in EAI between F and G
B
Difference in EAI between G and H
Ans) let the total be X
EAI of F=(30/100)*X
EAI of G=(40/100)*X
EAI of H=(60/100)*X
Col a:
diff in EAI b/w F and G
(40/100)*X-(30/100)*X
=(10/100)*X
Col b:
diff in EAI b/w G and H
(60/100)*X-(40/100)*X
=(20/100)*X
171) Certain no. of people were being checked for a certain disease. It was found that 10% of them were below 20yrs and had that disease. It was also found that all the people who were found to have that disease, 60% of them were 20 or above 20. Find fraction of people who were found to have that disease
Ans) let x are total no of persons
ley y be persons infected
no of persons infected below 20yrs=0.1x
no of persons infected above20 or equal to 20=0.6y
total no of persons infected=0.1x+0.6y----------------A
also 0.4y=no of persons infected below 20 yrs
so 0.4y=.1x
0.6y=0.15x-----B put this in eqn A
fraction =[0.1x+0.15x]/x
=0.25
1)got DI on probabality that was very easy you just need to know basics of probability
it had two questions they were single bar graphs with very easy to calculate numbers
2)another DI was on percentage given in pie graphs was bit tough but can manage if you are thorough wid percentage . it had two questions
3) .32(597)/ .987 asked to find the appromate value iam not sure of values but it was of this model options werelike 20 ,60 etc
4) I cant remember full question there is dinner hall one should be selecting from each of these there are 5 spoons, 4plates, 3dishes how many ways can select.
My graph question was some thing like this It is a column graph. The white column indicates the No. of people moving either out of the city or out of the state.And the black one indicates the no. of people moving out of the state. I don’t remember the exact values but I know all the exact answers
5)Ratio of the No. of people moving out of the city but not out of the state to the no of people moving out of the state is the highest for which group,
Ans. 60 to 69
6)The no of people under 10 and in 10 to 19 is what percent of the total
Ans. 33%
Another graph showed the marks obtaines by 11 students in two test. Test 1 on the x axis and test 2 on the y axis
7)What is the median mark of the class
Ans.120
8)In any test no. of the students which get marks below 40 are what percent of the total.
Ans. From the graph it will be L M and N in test 1 and L and P in test 2 are those who
get marks below 40 i.e. a total of 4 students (and not 5,because L is repeated).
Therefore 4 is what % of 11…..and that’s the ans.
9)some Di was given on a graph of no.of couples and no.of dependents (bargraph).
answer of one Question on this is 10% (approx.) (in the option)
one more Quest on this is abt. meadian ..something like if no.of dependents increased by 2 .....what will be the median
a) 1 less
b) 2 less
c)No change
d)1 more
e) 2 more (ans:C)
172) The perimeter of the rectangle is 20 , a triangle was inscribed in the rect with its base equal to its length and height equal to its width . need to find out area of the rect ?
a) 10
b) 12
c) 24
d)20
ans) by elimination method only 24 satisfies
area n perimeter
Perimeter=6+4+6+4=20
Area=6*4=24
173) 3^n + 4 is divisible by 5 find the value of n
a) 23
b) 24
c) 25
d) 26
e) 27
Ans) by elimination method
In 3^n+4
If n is divisible by 4 then units place of 3^n is 1
24 is the only option divisible by 4
Now 3^24+4 have 5 in its units place
B is the ans
174) P and N are integers P^2 = 5N
Col A Col B
N 3
ANS) : D
175) -10<>
Col A
Y
Col b
-15
ans) case1:
let x=6
x+y=-9
Then y=-15
Cola and colb are equal
Case 2:
Letx=9
X+y=19
Then y=10
cola > colb
Ans is D
176) k = y / x and k = 1/x + 1/y ; express k in terms of y
a) 1/( y-1)
b) 1/(y+1)
c) y/(y+2)
d) other options I don't rem
Ans) x=2 and y=2 satisfies both K expressions
K=2/2=1
k=1/2+1/2=1
By elimination method
Only 1/(y-1) satisfies
1/(2-1)=1
Ans is A
177) The equation was like this (5,00,000 * P / 100-P)and if P is 99 and 90
Then what is the diff when P=99 and P= 90
ANS ) 5,00,000(99-90/10)
5,00,000*90
= 450,00,000
178) A square was inscribed in a circle and asked to find out area between the
the arcOf the circle and the side of the square ?
Ans ) r=radius of circle
Diameter=diagonal of square=2r
Side of square=a
a^2+a^2=4*r^2
a=root2*r
area of square=2*r^2
area of circle=pi*r^2
difference b/w areas= pi*r^2-2*r^2
area between the
the arcOf the circle and the side of the square=
¼( pi*r^2-2*r^2)
=r^2/4*(3.14-2)
=0.285r^2
179) x <>
a) -3/2
b) -1/2 =
c) 0
d) 1/2
e) 3/2
Ans) elimination method
only B satisfies the given expression
180) p = 2^-2002, q = 2^1000
col A
4p
colB
q^-2
Ans )cola:
4p=4/2^2002=4/(2^2000*2^2)=1/2^2000
Colb:
q^-2=1/q^2=1/2^2000
Ans is C
181). x=|x|, y>0...which is -ve..
Ans) x =|x|
x=+x or –x
y>0
x can be -ve
182) cola.
((4.01)^3 - (1.97)^3)/(1.98)
Colb
18
Ans) cola: take approximate values
4.01=4
1.97=2
1.98=2
((4)^3 - (2)^3)/(2)
(64-8)/2=56/2=28
Colb:
8
Ans is A
183) . col a (root 2 * root 3)=root 6
col b :root 5
ans is B
184) if the ratio of circumference of two circles are 4:1. Then find the ratio of their diameter
ans:- )
(2*pi*r1)/(2*pi*r2)=4/1
r1/r2=4/1
(2*r2)/(2*r2)=d1/d2=(2*4)(2*1)
=4/1
Ans is 4:1
.
185) if A1 = 5; A2 = 10; and A3=(10)pow5; and An = (An-1)pow(An-2) where n>2
col a:no of digits in the 5th term
col b:5,000,001
Ans) consider col a
Now you know a1=5
a2=10
a3=10^5
And we have an formula i.e an=[a(n-1)]^[a(n-2)]
you need a5........Just substituite n= 5 in question .....
so a5= [a(5-1)]^[a(5-2)]
= a4^a3
We dunno a4.......calculate a4.............Just substituite n= 4 in question .....
a4= [a(4-1)]^[a(4-2)]
=a3^a2
=(10^5)^10
=10^50
Subs back again a5= a4^a3
a5 =a4^a3 =(10^50)^(10^5) =(10^50)^(100000)
=10^(5000000)
there fore no of digits 5000001
Ans is C
186) 24%passed in m1. 75%passed in m2. and 23%failed in either. then find the people passed in both.
ans)
U=union
^= interswction
People passed in either =
P(A U B)=100-P(A^B)
=100-23 = 77%
People passed in both=
P(A^B) = P(A)+P(B)-P(A U B)
=24 + 75 - 77 = 22%
ANS IS 22%
187) . ((x)^(n+1)/(x)^(n-1))+((x)^(n-1)/(x)^(n+
1))
ans)
[x^2(n+1) + x^2(n-1)] / x^(2n)
[( x^2n*x^2) + (x^2n*x^-2)]/x^(2n)
X^(2n) *[ x^2+ x^-2 ] / x^(2n)
X^2 + x^-2
X^2 + 1/x^2
188) Col A: The no. of even squares that are less than 100
Col B: The no. of odd squares that are less than 100
ans)
even squares are=0,4,16,36,64
odd squares are=1,9,25,49,81
ans is C
189) . (X) pow (2) = (y) pow (2) + 5;
Col A: X
Col B: Y
answer is D. can't be determined from the information
190). i got the triangle question in triangles.
/|
/ |
/ |
/ |
|\ 90 |
| \ |
| \ |
|90_\|
and they gave the other angles as x,y,w,z.
They asked the relations between them
For this I and II and III all are correct.
SO the option is 5.
dont brain storm at this question simply put the option 5.
191) A line is passing through (0,10) and (5,0)
There is one more line with slope m parllel to this line
Col A: m
Col B:-1/2
ans)
Given
(x1,y1)=(0,10)
(x2,y2)=(5,0)
Slope m of the parallel line is equal to the given line passing through (0,10) and (5,0)
Slope of line through the give points
=(y1-y2)/(x1-x2)
=(10-0)/(0-5)
=-2
Cola: Slope m=-2
Colb: -1/2
Ans is B
192)
so ter r two parallel lines vertically...two transversals r drawn.....such tat they meet at one of the parallel lines...and a triangle is formed...
col a:one side of the tri
colb:another side..
Ans) ans should be D….bcoz accoding to given information
Triangle formed can be any of these
* Righ angle triangle
*Isosales triangle
*Equilateral triangle
*triangle with all sides unequal
*isosales right angle triangle
So ans is D
193)x is +ve integer & is a factor of 3x+1
Col A-------------------------Col B
(-1x)---------------------------1
Ans) let x=1
3x+1=4
1 is a factor of 4
Cola: -1x=-1
Colb: 1
Ans is B
194)Col A----------------------------Col B
Sqrt(24)-1-------------------Sqrt(10)+1
Ans)
Cola:
sqrt(24)-1
= 4.x-1
=3.x
Colb:
sqrt(10)+1
=3.x+1
=4.x
Ans is B
195)0
Col A------Col B
4s-1 ------ 5r+( )
Dont remember xactly its easy
Ans) let s=1 and r=2
Cola: 4-1=3
Colb: 10+()
Question is not clear….on substitution u get ans
196) p,q have diff x-co ord's
product of x co-ords of all points on segment PQ are -ve.
Col A ------ --------------Colb
slope of segment PQ ---- -1
Ans)
we don’t know any information abt Y co-ordinates
slope of segment PQ cqn’t be determined
ans is D
197)
Col A ------ -----------------------------Col B
s.d. of 10,30,50,70,90------------ s.d. of 10,45,50,55,70
Ans)
cola :
mean=50
sd=SQRT[(40^2+20^2+20^2+40^2)/5]
colb:
mean=46
sd=SQRT[( 36^2+4^2+9^2+34^2)/5]
by comparing SD numerators of cola ans colb
with out calculation we can say cola is greater
ans is A
198) 1,2,3,4,5 no's.............asked to find the probability when any two no's are taken such that their product is odd no........
Ans)
total no of odd no’s=3
probability of taking first odd no
=3/5 (3 odds of given 5 no’s )
probability of taking 2nd odd no
=2/4 (2 odds of remaining 4 no’s)
Total probability=3/5*2/4=3/10
199) n is a positive integer,n-2 is multiple of 3,4,5,6
col a:least of n
col b:362
Ans)
(n-2) is a multiple of 3,4,5,6
Multiply 3*4*5*6=360
360 is a multiple of 3,4,5,6
Divide 360 by any of the numbers given
Let us divide by 6
360/6=60
60 is also a multiple of 3,4,5,6
n-2=60
n=62
colb is greater
ans is B
200) the mean of m men is 54 and f womn is 60.and mean of m and f combined is 58.then
columna=m
columnb=f
sol)
t1/m=54 =>t1=54m
t2/f=60 =>t2=60f
(t1+t2)/(m+f)=58
(54m+60f)/(m+f)=58
54m+60f=58m+58f
4m=2f
f=2m
no of female=2 * no of male
colb is greater
ans is B
201) hexagon was inscribed in circle....and was asked to compare diagonal of hexagon n length of arc...
ans) length of the diagonal of a hexagon = diameter of the circle
length of arc > diameter of circle
202) . 14^n is divisible by 32 where n is integer
cola: n colb: 4
ans)
given 14^n is divisible by 32
(2*7)^n is dividible by 32
(2^n)*(7^n) is divisible by 2^5=32
[(2^n)*(7^n)]/(2^5)
By comparing numerator and denominator
7^n cannot be divisible by 2^5
2^n is divisible by 2^5 when n>=5
n minimum value=5
cola is greater
ans is A
203)
r1 = 13.2, 14.2,15.2,16.2,17.2,18.2
r2 = 13 x .2, 14 x .2 , 15 x .2 , 16 x .2 , 17 x .2 , 18 x .2
r3 = 13/.2, 14/.2, 15/.2, 16/.2, 17/.2, 18/.2
was asked to arranges SD in ascending order
ans)
let SD of r1= z
SD of r2 = (SD of r1) * 0.2=z*0.2
SD of r3=(SD of r1)/0.2=z/0.2
r1 = z
r2=z/5
r3=5z
SD’s in ascending order
r2 r1 r3
204) . a number n is divisible by 17 n 13..
cola n
colb 442
ans)
17*13=221
Minumu value of n divisible by 17 and 13=221
442 is also divisible by 17 ans 13
Ans is D
205). 2*x^3 + A* x^2 + B*x + 5 = 0...this is not the exact equation but it was smthing like this....it was stated that equation has three roots... and if x= -1 and x= 2 are two of dem then find value of A
Ans)
2*x^3 + A* x^2 + b*x + 5 = 0
Above equation has 3 roots
2 roots are given x=-1 and x=2
2 roots are enough to find A …..
bcoz there are only 2 unknown variables A & B
substitute x=-1 in the equation
A-B+3=0 ---- 1
substitute x=2 in the equation
4A+2B+21=0 ----- 2
SOLVING EQUATIONS 1 & 2
A= -9/2
206)if x>60 and y>60 what is the approximate value of
(x+(1/y))/12x
.ANS)
Let
x=60.00001 =60 (approximatelt)
Y=60.00001 =60 (approximatelt)
(x+(1/y))/12x =
(60+(1/60))/(12*60)
=3601/(60*60*12)
=3601/(3600*12)
1/12 (approximately)
207) cola:Nos divi by 3 b\w 1 to 50
colb: Nos divi by 3 b\w 51 to 100
ans:)
208)
cola: -2^-3 colb: -4^-3
ans)
cola:
-2^-3
=1/(-2)^3
= -1/8
colb:
-4^-3
=1/(-4)^3
=-1/64
-1/64 > -1/8
Ans is B
209) ) the quest ws lik..... x>1
x*=x\(x-1) which of foll is true.......
1. (x*)*=x*
2. 1/x*=x*
3. (2x*)=2(x)*
4. don remm........
Ans)
ans is (2x*)=2(x)*
(2x*)=(2*x*)=2(x*)
210) In company 1/4 of emp are archit.If 60 emp are added out of which 50 r archit
than ratio of archi changes to 1/3.If No emp leaves the job in all there r how many
options....180,360,420,720 don remm..................
Ans)
let initial no of employees=x
architects=x/4
60 added to x = x+60
Out of 60 ….50 are architects
Total no of architscts=(x/4)+50
ratio of archi changes to 1/3 =1/3(x+60)
(x/4)+50=1/3(x+60)
By solving x=360
Total no employees=x+60=420
Ans is 420
211) x<1>
ans)
given x<1>
so x+y <>
ans is B
212). (1/c)+(1/c^2)+(1/c^3) = x/c^4 c = 10 x?
Ans) (1/c)+(1/c^2)+(1/c^3) = x/c^4
(1/10)+(1/10^2)+(1/10^3) = x/10^4
(10^4/10)+(10^4/10^2)+( 10^4/10^3) = x
10^3+10^2+10=x
X=1110
213)x>79999
col a
digit in 1000 of x
colb
6
ans) given x> 79999
case1 :
x=80000 > 79999
1000 digit of x =0 <>
Cola <>
Case2:
X=89999>79999
1000 digit of x= 9 > 6
Cola > colb
Ans is D
214) i got the field problem with r sections and t farms....but u need to change that there are 5 workers and the work is equally divided among them and betty and rachel are 2 of the 5 workers.rest is same
cola
amount of betty
colb
rt/4
ans) amount of betty=rt/2
ans is A
215) )Median of 50 numbers is 54. median of another 60 numbers is 56
colA:
wat is the median of the total 110 numbers
col B:55
Ans)
data insufficiant
ans is D
216) If first four letters of a employees batch no are formed by all alphabits except a,e,i,o,u,Y and nest two can be formed by digits 0 to 9 wat is the max employees possibe....if the repetation is considered
Ans)
26-6(a,e,i,o,u,y)=20
0-9=10
Ans is 20*20*20*20*10*10
217) In year 97 salary of A n B are same ...in 98 a sal increased by t percent and b sal inc by m % ...n in 99 A sal inc by m% and B sal by t%....Col A sal of A in 99 col B sal of B in 99
Ans )
Let initial salary=100
t=10%
m=20%
yr 98
salary of A=100*110/100=110
salary of B=100*120/100=120
yr 99
salary of A=110*120/100=132
salary of B=120*110/100=132
ans is C
218) The no of ways in which 6 things can be divided into two diff groups containing 3 things and 3 things.......
Ans)
6!/(2!*3!*3!)
=10
219 ) x/7reminder 3
find remainder of (2x-1)/7
ans)
let x=10
(2x-1)/7
=19/7
Reminder=5
220)x/5remainder 3
colA colB
(x^2-7)/5 4
Ans)
Let x=8
Cola:
(x^2-7)/ 5
(64-7)/5
57/5
Reminder= 2
For any value of x reminder=2
Colb: 4
Ans is B
221.
1/4^n <>
col a
n
col b
6
Ans)
Minimum value of n=5
Bcoz 4^5=1024
1/1024 <>
n can be any value >=5
ans is D
222) .G gallons of water in a tank, if X gallons/hr--water flowing inward,Y gallons/hr water flowing outward, condition Y>X..then how much time it takes to so that the tank capacity becomes G/2 gallons of water.
Ans)
G is the capacity of water in container
now x
hence more water flows outward than inward
hence total water flowing outward is (y-x) gallons/sec
hence total capicity at this stage is (y-x)*t gallons
also time taken to fill up the container by g/2 gallons is:
g/2 = (y-x)*t
hence, t = g/2(y-x)
223) . A circle C is shown which passes through (1,6) with origin O lying inside C. The
center of the circle is shown C'.
Col A = radius of C ; Col B= sq.root(37).
ans) is D
224) .the perimeter of a right isoceles triangle is 1+root2.what is the are of the triangle.
ans)
Perimeter=
x+x+xroot2=1+root2
x=(1+root2)/(2+root2)
x= 1/root2
area=1/2*x*x
½*1/root2*1/root2
=1/4
225) z>y>x>1
colA colB
z(x+y+1) y(x+z+1)
ans)
For all x,y,z values
Cola > colb
Ans is A
226) if p is a positive integer then how many values will there 4 p such that 36p is a factor of 720(don't knw the no exactly).
ans )
cola
values of p
colb
8
for p=1,2,4,5,10,20
36,72,144,180,360,720 are the factors of 720
Total values of p=6 <>
Ans is B
227) Given a triangle with two angle 60 (which means it is an equilateral triangle ) and two side are given as x+4 and y-3
Col A Col B
x y
ans)
it is an equilateral triangle
sides are equal
x+4=y-3
y=x+4
y is greater
228) there is a 4*4*4 cube ..it is painted on all its 6 faces .. then it is cut in 1*1*1 cubes .. nopw randomly a face is pick frm any cube .. probability that face is colored one ..?
ans)
total no cubes of side=1
=64
No of cubes which are painted
=56
probability that face is colored one
=56/64
=7/8
229) )if n/12 rem is 5..
wat is val when n*n/8..
ANS)
Let n=17
17/12 rem =5
17*17/8 rem =1
Ans is 1
230)one more Quest on this is abt. meadian ..something like if no.of dependents increased by 2 .....what will be the median
a) 1 less
b) 2 less
c)No change
d)1 more
e) 2 more (I more
Ans)
Median of a certain series will not be changed by increasing dependents by same value
Ans is C no change
231) Fresh fruit contains 72% water and dry fruit contains 20% water. How much dry fruit from 100 pounds of fresh fruit
can be obtained
ans) 38 gm dry fruit
232) .if a cylinder is empty and it takes 4 hours to fill it and after 2 and a half hours 150 cubic feet was filled, what is the capacity of the tank.
Ans)
5/2 hr----150 cubic feet
1 hr----------x?
X=150/(5/2)
=60 cubic feet in 1 hr
Capacity of the tank=60*4=250 cubic feet
233) .which has the greatest prime factor 66 or1000.
ans)
prime factors of 66
=2,3,11
Prime factors of 1000
= 2,5
66 has greatest prime factor
234) 2x^2-2x=0.Xnot equal to 2
col a
x
col b
2
ans)
2x^2-2x=0
x^2-x=0
x(x-1)=0
(x-0)(x-1)=0
X=0 or x=1
Col b is greater
Ans is B
183)
col a (root 2 * root 3)=root 6
col b :root 5
ans is A
231)
Fresh fruit contains 72% water and dry fruit contains 20% water. How much dry fruit from 100 pounds of fresh fruit
can be obtained
ans) A fresh fruit contains 72% of water è 28% of solid
In a 100 pounds fresh fruit we will get 28 pounds solid.
& also given A dry fruit contains 20% of water è 80 % of solid
è with 80 pounds solid we can create 100 pounds dry fruit
Then with 28 pound solid, how many dry fruit
i.e. (80/100) x 28 = 35 gh...... 35 gm dry fruit
228) there is a 4*4*4 cube ..it is painted on all its 6 faces .. then it is cut in 1*1*1 cubes .. nopw randomly a face is pick frm any cube .. probability that face is colored one ..?
ans)
total no of faces=6*64
=64
No of faces which are painted
=6*16
probability that face is colored one
=(6*16)/(6*64)
=1/4
235) (x-2)^(x-4)=4 cola x, colb 4
ans)
for any value of x given xpression is no satisfied
ans is D
236) A’s salary is 2000greater than B’s .if A’s salary is increased by 10% and B’s salary increased by 15%
col a
salary of A after incr
colb
salary of B after incr
ans)
let x be salary of A
salary of A after 10% inc
1.1x+2200
salary of B after 15% inc
1.15x
Case1:
if x=10,000
cola > colb
case 2:
If x=1,00,000
Cola <>
Ans is D
237) if n divided by 7remainder is 3 wht is remainder when (n+n+n)/7
ans)
Let n=10
10/7 rem =3
(n+n+n)/7
=(10+10+10)/7
=30/7 rem=2
238) x^2 - 2x=0 and x is not equal to 2
colm a colm b
2x^2 0
ans )
x^2 - 2x=0
(x-0)(x-2)=0
Given x not = 2
X=0
Cola = colb
Ans is C
239)1/x = y/1
where x and y are positive integers
colm a colmb
x y
Ans)
If x =1 and y =1 only above condition is satisfied
Cola=colb
Ans is C
it was abt percent of people who have moved form their state.
do remember frds dont waste time in this i hv almost spend 6 mins in this one, ans is
people betn age of 60-69.
8 was depend upon same graph.
they have asked me about the ratio of people who didnt moved to the people who has moved for age betn age 30-39
ans was 83%
240) COL A COLB
5/8 ROOT5/8
Ans)
colb > cola
ans is B
241) |x+9|=X+5, wat is the value of X
Ans)
X+9=x+5 (this is not possible)
Or
X+9=-(x+5)
2x=-14
X=-7
242) .two lines l1 and l2 are parallel... points (1,1) and (3,2) are on the line l1. what is slope of l2.
Ans: )
Given lines are parallel…so slopes will be equal
Slope of l1=slpoe of l2
=(2-1)/(3-1)
=1/2
243). x*=x/(x-1)
x not equal to 1
1. (x*)*=x
2. 1/x*=x*
3. (2x*)=2(x)*
4. don remm........
Ans)
(X*)*
= [x/(x-1)]*
= [x/(x-1)]/[ (x/(x-1))-1]
=x
Option 1 is the ans
244) .A triangle is given.. AB=8,BC=6, Ac=y and Angle ABC=x and x<90.
cola==> y
colb==>10
Ans)
If x=90 then y=10
If x<90>
Ans is B
245) . x+2y <-6
cola==> |x+2y|
colb==> 5
ans)
given x+2y <-6
value of x+2y is –ve
mod of a –ve value is always +ve
|x+2y|>6
Ans is A
246) (1.1)^2/(0.9)^2 + (0.9)^2/(1.1)^2
cola colb
value 2
Ans)
(1.1)^2/(0.9)^2 + (0.9)^2/(1.1)^2
=(121)/(81)+(81)/(121)
= approx (3/2+2/3) > 2
Ans is A
247) Area of a equilateral triangle inscribed in a circle of radius R.
Ans)
Side of eqilateral triangle s =root3R
Area of equilateral triangle =(root3/4)*s^2
= (root3/4)*(root3R)^2
=(3root3/4)R^2
248)the ratio of males to females is 1:x (x>0)
total no of employees 253
no of females in terms of x
some options were
253x/(x+1)
253/(x-1)
253(x+1)
Ans)
No of females in terms of x
=253*x/(1+x)
=253x/(x+1)
249) some other ques were
1,2,3,4,5
pick any 2nos probability that product willl b even
Ans)
Probability that product will be evev=1- (Probability that product will be odd)
1-3/10
=7/10
250) 2^-1, 3^-1 and 4^-1
x is any one of the above
y is sum of the other 2
col a
x
col b
y
Ans)
Case 1: 1/2<(1/3+1/4)
Case 2: 1/3 <(1/2+1/4)
case 3: 1/4 <(1/2+1/3)
Ans is B
251) X took 3/8 of a roll of ribbon. Of the remining Y took 2/5 of the ribbon. At this point 45in was remining on the roll.
col A-the length on the roll
col B-150
Ans)
X=3/8 of ribbon
Remaining= 5/8
Y= 2/5*5/8 = ¼ of ribbon
Total ribbon used=3/8+1/4=5/8
Remaining= 3/8 th of ribbon=45
Length of ribbon=45+75=120 <>
Ans is B
252) A walks with a speed of 65mil/hr to some place and returns with a spped of 35mil/hr. Find the difference in speed in KM/HR(I km=0.621 miles)
Ans)
Diff in speeds= (65-35)/0.621
=30/0.621
=48.3 Km/hr
253) A group of boy go to play a game. The boys arriange themselves into 8 groups containing 6 boys per group and two are left. After some time, the boys re arrarrage the selves into groups containing equal number of memebers and one is left. What is the number of boys in each group.
Ans-c)
Initially 8(groups)*6(boys per group)+2(left)=50
After rearrangement
7(groups)*7(boys per group)+1(left)=50
No of boys in each group=7
254) Ann buys w kgs of fodder per week to feed her sheep. each sheep eats x kgs/day.
col a-No. of sheep Ann has
col b-7w/x
Ans)
W kgs per week
w/7 kgs per day
given each sheep eats x kgs/day
no of sheeps Ann has =
(w/7)/x
w/(7x)
colb is greater
ans is B
255) A line l passes through points (n, n+1) and (1,1) and lime m passes through (n, n+1) and point (2,2). and n>0
col a-slope of l
col b-slope of m
Ans)
Case 1:
Let n=1
Slope of l > slope of m
Case 2:
Let n=2
Slope of l <>
ans is D
256) n>5
col a: 1/n+1/(n-1)
col b: (1/n)^2+(1/(n+1))^2
Ans) is A
257) x and y are two numbers such that x^2y^2=22. what can be the sum of x and y
Ans-)
Root22 + 1
Or
Root11 + root2
Depends on the options given
258) A professor gives A, B, C, D and E to a class of students. What is the minimum number of students so that atleast 6 students get the same grade.
a)24 b)25 c)26 d)27
Ans-c)
A--- 1, B---2, C---3 ,D---4, E---5
again...
A---6, B---7.. & SO ON
so after 5 rounds, i.e. 25 students, 5 students will have 5 same grades....
so the next one will be the first one to get 6 same grades
so the ans is 26
259) a bag x contains 6 fruits- 3 apples 3 pears
a bay y contains 8 fruits- 4 apples 4 pears wat is the prob tat 2 apples ra taken out simultaneously
Ans)
Prob of taking 2 apples from bag x
= 3/6*2/5=1/5
Prob of taking 2 apples from bag y
= 4/8*3/7=3/14
Prob of taking 1st apple from bag x and 2nd apple from bag y
=3/6*4/8=1/4
Total probability
=1/5+3/14+1/2=26/35
260) A(3,0) B(3,4)
p is a point that is equidistant to the points a and b
ans)
There are infinity points which are equidistant from A and B
Ans is D
261) IN A PARALLELOGRAM 6X,120 ARE THE OPPOSITE ANGLES
AND OTHER IS 3Y FIND
COLA:X
COLB:Y
ANS)
6x=120
X=20
Sum of other two opposite angles=360-(120+120)=120
3y=60
Y=20
X=y
Ans is C
262))this is my first questin regarding co-ordinate geometry. three points were given (2,2),(3,6),and (6,5) and asked to find whether angle x
col a x col b 90
263) x<2>
colA xy colB 6
Ans)
Case :1
x=1 and y=2
xy=2 <>
case 2:
x=-2 and y= -4
xy=8 > 6
ans is D
264) |6-x|-|-x-3| and value x=3 got to find the result
Ans)
|6-3|-|-3-3|
=|3|-|-6|
=3-6
=-3
265) 4 numbers where given 17, 11 , 60 , 172 ( not sure about 172 ).....and we where supposed 2 arrange #'s as per the increasing order of the least Prime factor # divisible...
Ans)
Least prime factor of 17 =17
Least prime factor of 11=11
Least prime factor of 60=2
Least prime factor of 172=2
order depends 4th value ( not sure about 172)
266) xy not equal to 0
col a colb
/-x-y/ x+y
ans)
case 1:
x=1 y=1
cola: |-1-1|=2
colb: 1+1=2
cola=colb
case 2:
x=1 y=-2
cola:|-1+2|| =1
colb:1-2=-1
cola > colb
ans is D
267) If k and n is divided by 9 we get remainder as 2 and 5 respectively.k>n and if k-n is divided by 9 then wat is the reaminder.
Ans)
Let k= 29 and n=14
k-n= 15
15/9 rem = 6
268) r - r^3 = r^3 - r
col a: r
col b : o
ans)
r can be -1 or 1 both satisfies above condition
ans is D
269) . perimeter of triangle is given as 37 side AB = BC, side AC is 4 greater than 1/5 of the either sides.
cola: side AC
col b: 7
ans)
let AB=BC= x
AC=4+x/5
AB+BC+AC=37
x+x+4+x/5=37
x=15
AC=4+15/5=7
270) col a = (a+b)^3 col b=a^3+b^3 ans :A
Ans)
Case 1:
If a=0 and b=0
Cola=colb
Case 2:
If a=1 and b=1
Cola=8
Colb=2
Colb>cola
Ans is D
271) if susans salary increased by 10% and his wife's salary is increased by 15% whose sal is more after increase if before increase susans sal was 2000 more than his wife grady?
col a: susans sal col b: his wife grady
ans) ans is A
272) There are 4 officers and 5 jawans. In how many ways a group of 6 people can be formed if the group consists exactly 1 officer
Ans)
4c1*5
=20
273) A survey was conducted. It came out that 87 people liked red 91 liked silver 91 liked blue. Now there were 9 who liked only red, 10 who liked only silver and 12 who liked only blue. There were a total of 40 who liked all these colors. Find the total number of people who liked red or silver but dint like blue?
Ans)
Use venn diagram
Let people who liked only R an B be x
Let people who liked only R an S be y
Let people who liked only B an S be z
X+y+40+9=87
Y+z+40+10=91
X+z+40+12=91
people who liked red or silver but dint like blue
=9+10+y
=9+10+20
=39
274) Sixty-eight people are sitting in 20 cars and each car contains at most 4 people. What is the maximum possible number of cars that could contain exactly 1 of the 68 people?
(A) 2 (B) 3 (C) 4 (D) 8 (E) 12
Ans)
Given atmost 4 in each car
68 people can be arranged in 17 cars with 4 people in each car
3 cars are eampty
Consider any car out of 17 with 4 people
From that car arrange 3 people in 3 eampty cars with 1 each
maximum possible number of cars that could contain exactly 1
=3(eampty cars with 1 each)+1(distributed car with 4people)
=4 option D
275) In an election between two candidates who got 45% of the valid votes was defeated
By 150 votes. Find the total number of votes, if 80% of the votes polled were valid.
1725
1775
1825
1850
1875
Ans)
Let total no of votes=x
Valid votes=0.8x
45/100(0.8x)+150=55/100(0.8x)
Solving we get
X=1875
276) 7 b) 6 c) 5 d) 3 e) 1
23) Col A--- ----w (2x +2y + 2z + 1)
Col B ----w (x + y + z)
Ans) D
277) Five years ago, Beth’s age was three times that of Amy. Ten years ago, Beth’s age was one half that of Chelsea. If C represents Chelsea’s current age, which of the Following represents Amy’s current age?
A. c/6 + 5
B. 2c
C. (c-10)/3
D. 3c-5
E. 5c/3 - 10
Ans)
B=3A
Amys current age= B/3+5
B=CH/2
CHeseas current age=C=2B+10
B=(C-10)/2
Amys current age=
(C-10)/(2*3)+5
(C-10+30)/6
(C+20)/6 (this is my ans …. If u get any other ans from options plz inform me)
278) A portion of $7200 is invested at a 4% annual return, while the remainder is invested at a 5% annual return. If the annual income from both portions is the same, what is the total income from the two investments?
$160
$320
$400
$720
$1,600
Ans)
Amt invested at 4% be x
Amt invested at 5% be y
X+y=7200
4x/100=5y/100
4x=5y
x+4x/5=7200
x=4000
4% of x=160
Total income=160+160=320
279) m n are positive integers.
Col a: 1/ (2m) ^n^m
colb: 1/2^mn
Ans)
Case 1: if m=1 and n=1
Cola=colb
Case 2: if m=2 an dn=2
Cola <>
Ans is D
280) one quest to find the length of fencing of a circular park with dist bet 2 poles as which surrounded is 2cms and max dist bet any to poles was given as 12 cms(max dist is nothing but diameter)
Ans)
Radius=6
Length of fencing=2*pi*r
12pi
281)y^x=1/16
colA:x colB:-3
Ans)
Y^x=2^(-4)
Or
Y^x=4^(-2)
Ans is D
282). (x-1)^2-1>0
a b
x 1
Ans)
Let x=3
(3-1)^2-1>0
3>0
Let x=-3
(-3-1)^2-1>0
15>0
Ans is D
283) . cola
{(5.01)^2-(2.89)^2}/1.98
colb
8
Ans)
Let (5.01)^2-(2.89)^2=x
X > 16
Let 1.98=y < 2
Now (x/y) > 8 from above cond
cola Is greater
284) .y>x>0
a b
1/x y
ans)
if x=1/4 and y=1/2
cola > colb
if x=2 and y=4
cola < colb
ans is D
285) 5 , 10, 10^5,...
(n>2) n^th term= [(n-1)th]^(n-2)th
colA==>no of terms in the 5th term
ColB==> 500001
ans)
5th term=4th term^(3rd term)
=((10^5)^10)^(10^5)
=(10^50)^100000
=10^5000000
=5000001 > 500001
Ans is A
286) If x is a positive no, when it is divisible by 9 it leaves remainder 2.when n is divided by 9 leaves remainder 5. X should be greater than n what is reminder if (x-n) is divided by 9
Ans )
assume X to be 20 and y to be 14...x-y will be 6...when divided by 9 reminder will be 6...
287) xy=3
x^2+y^2=22
find the value of x+y
Ans)
x^2+y^2=22
(x+y)^2=22+2xy
(x+y)^2=28
X+y=root28
288) which of the following cannot be t factor of 2^n . 3^k n and are pos integers
6
8
27
42
54
ans) 42
289 )if n number get a avg of 8 and n+2 numbers get an avg of 6.find the combined aveerage.
Ans)
let sum of n numbers=x
x/n=8 => x=8n
let sum of n+2 numbers=y
y/(n+2)=6 => y=6n+12
combined average=
(x+y)/(n+n+2)
(14n+12)/(2n+2)
(7n+6)/(n+1)
290) perimeter of triangle is given as 37 side AB = BC, side AC is 4 greater than 1/5 of the either sides.
cola: side AC
col b: 7
ans)
given
AB+BC+CA=37
AC=4+AB/5
AC=4+BC/5
AC+5(AC-4)+5(AC-4)=37
Solving we get AC=7
Cola = colb
Ans is C
291) a cake consist of 4 peaches and 5 bananas?
col a
no of peaches in the cake
col b
80% of bananas
Ans)
Cola:4
Colb: 80% of 5 =4
Ans is C
292) R is multiple of 3 and T is multiple of 7 if T and R are 2 digit no wat the least prodct of T and R \
Ans)
Least 2 digit multiple of 3=12
Least 2 digit multiple of 7=14
Least product=12*14=168
293) area is given as 150 square feet. ( 1 yard = 3 feet )
Col a) ------ No.of yards
Col b) ------30
ans)
no of yards=150/9 < 30
ans is B
294) In a company 23% of them are old people and above 15 yerars of experience and 76% are young people.. the 24% of the whole firm are below 15 years of experience... what is the % of apeople having below 15 yers experience and young person..??
Ans)
23% old & above 15 yr exp
76% young
100-(76+23)=1% old and below 15 yr exp
Total 24% below 15 yr exp
Young persons 15 yr below exp=24-1(old below 15 yr exp)
=23%
295) The price of book x is 5 times the price of book y.
On a particular day, y books were sold as many as 4 times
X books thus making business of $36.
What is the cost of x book?
Ans)
Price of x=5 times price of y
Let price of y=a
Price of x=5a
Y Books sold =4 times x books
1*5a+4*a=36
a=4
cost of book x=5a=$20
Friday, August 24, 2007
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